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List:       pykde
Subject:    Re: [PyQt] Problem quitting QApplication using qt_app.exec_()
From:       darkpenguin <darkpenguin () yandex ! com>
Date:       2019-03-22 12:15:01
Message-ID: 1041821553256901 () myt4-bf1cdac1d2eb ! qloud-c ! yandex ! net
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I'm also a Python beginner, so please take my words with a little pinch of salt, but \
I can at least explain the first problem.<div><br /></div><div>What does your \
fnQuit_button_clicked(self) code do? It *executes the application*, and when the \
application finishes, it quits with its return code. Not only that, but instead of an \
application, you're trying to execute a widget, which actually generates the \
error...</div><div><br /></div><div>Also, I'd say it's at least confusing that you're \
trying to instantiate your widget as a variable called "app", which is the source of \
confusion that led to this problem. And then you "run" the widget, which actually \
launches the application.</div><div><br /></div><div>I'd suggest to stick to the \
"normal" way of doing those things.</div><div><br /></div><div>First of all, change \
the three bottom lines to the following:</div><div><br /></div><div>myapp = \
QApplication(sys.argv) # Instantiate a QApplication</div><div>mywidget = \
LayoutExample() # Instantiate my widget</div><div>sys.exit(myapp._exec()) # Launch \
the application and exit with its return code</div><div><br /></div><div>Then, move \
self.show() to the constructor, and remove the run() function. The widget shows \
itself after it's constructed, and you don't "run" a widget.</div><div><br \
/></div><div>And finally, your Quit button should simply call self.close() . In this \
case, I would not even create a separate function for this; instead, I would simply \
connect the button directly to self.close (remember, without "()", since we are \
passing it and not executing it!). When this widget is closed, the application will \
exit.<br /><br />-- <br />darkpenguin</div>


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