[prev in list] [next in list] [prev in thread] [next in thread] 

List:       xsl-list
Subject:    Re: [xsl] Find elements with same key and merge sub-elements
From:       "Martin Honnen martin.honnen () gmx ! de" <xsl-list-service () lists ! mulberrytech ! com>
Date:       2023-09-26 19:42:08
Message-ID: 20230926154137.b328c747 () lists ! mulberrytech ! com
[Download RAW message or body]


On 26.09.2023 21:34, Larry Hayashi lhtrees@gmail.com wrote:
> Hi,
>
> I have an xml file containing dictionary entries with their
> meanings/senses. I'd like to find Entries that have 2 or more senses
> that have the same gloss. Sometimes an entry will have more than one
> sense but each sense will have its own unique gloss. For the entries
> that have senses with identical glosses, I want to merge those senses
> and their contents as shown below.
>
> Input
> <Root>
>       <Entry form="voiture">
>             <Sense num="1">
>                   <Gloss>car</Gloss>
>                   <Index>
>                         <IndexItem>automobile</IndexItem>
>                         <IndexItem>vehicle</IndexItem>
>                         <IndexItem>car</IndexItem>
>                   </Index>
>             </Sense>
>             <Sense num="2">
>                   <Gloss>car</Gloss>
>                   <Category>transportation</Category>
>             </Sense>
>       </Entry>
>       <Entry>
>             <!-- ...Etc.... -->
>       </Entry>
> </Root>
>
> Desired Output:
> <Root>
>       <Entry form="voiture">
>             <Sense num="1">
>                   <Gloss>car</Gloss>
>                   <Index>
>                         <IndexItem>automobile</IndexItem>
>                         <IndexItem>vehicle</IndexItem>
>                         <IndexItem>car</IndexItem>
>                   </Index>
>                   <Category>transportation</Category>
>             </Sense>
>       </Entry>
>       <Entry>
>             <!-- ...Etc.... -->
>       </Entry>
> </Root>
>
> Thanks in advance for any pointers as to what might be the most
> efficient approach.
>

It looks like a grouping problem so in XSLT 3 you can do something like
the following (it is not quite clear whether common elements of a group
of Entry elements with the same Gloss need to simply copied or also
somehow merged)


<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
        xmlns:xs="http://www.w3.org/2001/XMLSchema"
        exclude-result-prefixes="#all"
        version="3.0">

    <xsl:mode on-no-match="shallow-copy"/>

    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="Entry">
        <xsl:copy>
            <xsl:apply-templates select="@*"/>
            <xsl:for-each-group select="Sense" group-by="Gloss">
                <xsl:copy>
                    <xsl:apply-templates select="@*, Gloss, current-group()/(*
except Gloss)"/>
                </xsl:copy>
            </xsl:for-each-group>
        </xsl:copy>
    </xsl:template>

</xsl:stylesheet>
--~----------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
EasyUnsubscribe: http://lists.mulberrytech.com/unsub/xsl-list/651070
or by email: xsl-list-unsub@lists.mulberrytech.com
--~--

[prev in list] [next in list] [prev in thread] [next in thread]