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List:       xmlrpc-user
Subject:    [jira] [Created] (XMLSCHEMA-29) An element without "ref" and "type" attributes has not got any assig
From:       "Alexandr Klimov (JIRA)" <jira () apache ! org>
Date:       2013-08-17 21:31:47
Message-ID: JIRA.12664222.1376775025754.85378.1376775107901 () arcas
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Alexandr Klimov created XMLSCHEMA-29:
----------------------------------------

             Summary: An element without "ref" and "type" attributes has not got any \
assigned XSD type but should has got "anyType" XSD type.  Key: XMLSCHEMA-29
                 URL: https://issues.apache.org/jira/browse/XMLSCHEMA-29
             Project: XmlSchema
          Issue Type: Bug
    Affects Versions: 2.0.2
            Reporter: Alexandr Klimov


I faced with some trouble when I have tried parse following XSD:
{code:xml}
<?xml version="1.0"?>

<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
           targetNamespace="http://www.w3schools.com"
           xmlns="http://www.w3schools.com">

    <xs:complexType name="TestType">
        <xs:sequence>
            <xs:element name="stringElem" type="xs:string"/>
            <xs:element name="dummyElem"/>
        </xs:sequence>
    </xs:complexType>

</xs:schema>
{code}

A XmlSchemaElement object corresponds to *dummyElem* element has got *schemaType* and \
*schemaTypeName* fields equal *NULL*.

But I'm convinced that in this case \
{noformat}{http://www.w3.org/2001/XMLSchema}anyType{noformat} type should be assigned \
as type of the untyped element. My point of view based on following document: [W3C \
XML Schema Definition Language 1.1 | http://www.w3.org/TR/xmlschema11-1/], point \
3.3.2.1

This *anyType* type is defined in *org.apache.ws.commons.schema.constants.Constants* \
class but I have not found where it is used in any assignment during XSD parsing.

In my opinion, *org.apache.ws.commons.schema.SchemaBuilder#handleElementGlobalType* \
method should contains the third condition branch for a case when *type* and *ref* \
attributes are absent and *anyType* type should be set in the branch.

May be I misunderstand something in a XSD definition and *anyType* type can not be \
assigned in this case?  

Best regards
Alexandr Klimov.   

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