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List:       tomcat-user
Subject:    Re: Problems starting Tomcat 9.0.24 32-bit as a service
From:       Mark Thomas <markt () apache ! org>
Date:       2019-08-28 6:39:42
Message-ID: 7C6B6FD5-4A1C-47BC-8CA4-E8F02CF73A76 () apache ! org
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On August 27, 2019 5:40:57 PM UTC, Juan Ramirez <jramirez@nqueue.com> wrote:
>Hello,
>
>I'm currently having an issue with starting Tomcat 9.0.24 32-bit
>version as a service.

https://bz.apache.org/bugzilla/show_bug.cgi?id=63625


It seems to be specific to 32-bit Windows.

Still digging in to the root cause. You can use Tomcat9.exe from 9.0.22 as a workaround.

Mark


> After installing Tomcat9 using the windows
>service installer, I try to run Tomcat9 and get the windows service
>error:
>"Windows could not start Tomcat9 service on Local Computer. Error 1067:
>The process terminated unexpectedly." I tried looking in the logs to
>see what could have caused the error, but no errors are logged. The
>only thing I could find in the logs is in the commons daemon log file:
>
>[10860] Apache Commons Daemon procrun (1.2.0.0 32-bit) started.
>[10860] Debugging 'tomcat9' service...
>[10860] Starting service...
>
>I also tried running Tomcat9 through the executable (tomcat9.exe) and
>get the error: "Apache Commons Daemon Service Runner has stopped
>working." I have also tried manually installing Tomcat9 through the
>32-bit Windows zip and keep having the same errors as installing it
>through the installer. When I tried using the 64-bit version of Tomcat
>9.0.24, it seems to work fine and I'm able to launch it as a service,
>which leads me to belive that something maybe wrong with the 32-bit
>version only. I'm using AdoptJDK 12.0.2+10 HotSpot 32-bit for Windows
>10, as well as the 64-bit version when I tried the 64 bit version of
>Tomcat9. The last thing I tried was running Tomcat 9.0.24 32-bit
>through the command line window with the provided startup.bat file in
>the bin folder and I was able to run Tomcat9 and even reach the default
>web page. I'm just not able to run it as a windows service.
>
>Any and all help is appreciated, thanks.
>Juan


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