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List:       sas-l
Subject:    Re: SAS regex, suffix option
From:       toby dunn <tobydunn () HOTMAIL ! COM>
Date:       2004-12-31 17:28:30
[Download RAW message or body]

Ahh.... One more reason why reg expressions are for writing and not
reading...

By the way for all those interested my new email addy is
tobydunn@hotmail.com atleast till I getset up at my new shop.

Happy new years to you all...



Toby Dunn




From: "Chang Y. Chung" <chang_y_chung@HOTMAIL.COM>
Reply-To: "Chang Y. Chung" <chang_y_chung@HOTMAIL.COM>
To: SAS-L@LISTSERV.UGA.EDU
Subject: Re: SAS regex, suffix option
Date: Fri, 31 Dec 2004 11:27:42 -0500
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Comments: To: "Richard A. DeVenezia" <radevenz@IX.NETCOM.COM>
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On Fri, 31 Dec 2004 09:32:59 -0500, Richard A. DeVenezia
<radevenz@IX.NETCOM.COM> wrote:

 >I'm trying to use SAS regex to check for a pattern at the end of a string.
 >
 >Any ideas why the first oodles is matched instead of the last ?
 >
 >-----
 >data _null_;
 >  text = "oodles of snicker doodles";
 >
 >  rx = rxParse ( " oodles $s " );
 >
 >  call rxSubstr ( rx, text, pos, len );
 >  put pos= len=;
 >
 >  call rxFree ( rx );
 >run;
 >-----
 >pos=1 len=6
 >
 >Was expecting
 >pos=20 len=6

Hi, Richard,

If you want to check the end of the string, then you can use @0 -- the
beginning of the line is @1.

   rx = rxParse ( " oodles @0 " );

results in

   pos=20 len=6

You can also do something like below to match a word that ends
with 'oodles' (and a following white space or the end of line char) but
starts with something other than a space character:

   rx = rxParse ( " ~' '+ oodles $s|@0 " );

which results in

   pos=19 len=7 (which is interesting -- I think :-))

I think in sas regEx, both $s and $S matches with a white space character,
while in sas perlRegEx, $ matches the end of line.

Cheers,
Chang

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