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List:       ruby-talk
Subject:    Re: increasing counter whithin loop?
From:       Neil Stevens <neil () hakubi ! us>
Date:       2005-12-05 15:17:34
Message-ID: HPYkf.594$EB3.38 () trnddc09
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Patrick Gundlach wrote:
> Hi,
> 
> a very basic question...
> 
> I'd like to output the sequence "a b d e", by testing if the current
> element is == "b" then skip the next element and continue the loop. The
> obvious solution doesn't look rubyish to me, how could I use the first
> or second attempt to get the desired solution?

array = [1, :skip, :hidden, 2, :skip, :hidden, 3, :skip]

# Zipped to ensure i is uniquely index()ed
# Also makes sure use array non-destructively
zip = array.zip
for i in zip
	if i[0] == :skip
		zip.delete_at(zip.index(i) + 1)
	else
		puts i[0]
	end
end

Output:

1
2
3

-- 
Neil Stevens - neil@hakubi.us

'A republic, if you can keep it.' -- Benjamin Franklin

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