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List:       r-help
Subject:    Re: [R] Parallel assignments and goto
From:       Thomas Mailund <thomas.mailund () gmail ! com>
Date:       2018-02-27 16:46:37
Message-ID: 1ae639bf-a5d1-4cb1-84c6-0828139b32c8 () Spark
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I did try assign. That was the slowest version from what my profiling could tell, as \
far as I recall, which really surprised me. I had expected it to be the fastest. The \
second slowest was using the [[ operator on environments. Or it might be the reverse \
for those two. They were both slower than the other versions I posted here.

Cheers

On 27 Feb 2018, 17.16 +0100, Bert Gunter <bgunter.4567@gmail.com>, wrote:
> No clue, but see ?assign perhaps if you have not done so already.
> 
> -- Bert
> 
> 
> 
> Bert Gunter
> 
> "The trouble with having an open mind is that people keep coming along and sticking \
>                 things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
> 
> > On Tue, Feb 27, 2018 at 6:51 AM, Thomas Mailund <thomas.mailund@gmail.com> wrote:
> > > Interestingly, the <<- operator is also a lot faster than using a namespace \
> > > explicitly, and only slightly slower than using <- with local variables, see \
> > > below. But, surely, both must at some point insert values in a given \
> > > environment — either the local one, for <-, or an enclosing one, for <<- — \
> > > so I guess I am asking if there is a more low-level assignment operation I can \
> > > get my hands on without diving into C? 
> > > 
> > > factorial <- function(n, acc = 1) {
> > > if (n == 1) acc
> > > else factorial(n - 1, n * acc)
> > > }
> > > 
> > > factorial_tr_manual <- function (n, acc = 1)
> > > {
> > > repeat {
> > > if (n <= 1)
> > > return(acc)
> > > else {
> > > .tailr_n <- n - 1
> > > .tailr_acc <- acc * n
> > > n <- .tailr_n
> > > acc <- .tailr_acc
> > > next
> > > }
> > > }
> > > }
> > > 
> > > factorial_tr_automatic_1 <- function(n, acc = 1) {
> > > .tailr_n <- n
> > > .tailr_acc <- acc
> > > callCC(function(escape) {
> > > repeat {
> > > n <- .tailr_n
> > > acc <- .tailr_acc
> > > if (n <= 1) {
> > > escape(acc)
> > > } else {
> > > .tailr_n <<- n - 1
> > > .tailr_acc <<- n * acc
> > > }
> > > }
> > > })
> > > }
> > > 
> > > factorial_tr_automatic_2 <- function(n, acc = 1) {
> > > .tailr_env <- rlang::get_env()
> > > callCC(function(escape) {
> > > repeat {
> > > if (n <= 1) {
> > > escape(acc)
> > > } else {
> > > .tailr_env$.tailr_n <- n - 1
> > > .tailr_env$.tailr_acc <- n * acc
> > > .tailr_env$n <- .tailr_env$.tailr_n
> > > .tailr_env$acc <- .tailr_env$.tailr_acc
> > > }
> > > }
> > > })
> > > }
> > > 
> > > microbenchmark::microbenchmark(factorial(1000),
> > > factorial_tr_manual(1000),
> > > factorial_tr_automatic_1(1000),
> > > factorial_tr_automatic_2(1000))
> > > Unit: microseconds
> > > expr       min         lq         mean    median            uq         max \
> > > neval factorial(1000) 884.137 942.060 1076.3949 977.6235 1042.5035 2889.779    \
> > > 100 factorial_tr_manual(1000) 110.215 116.919   130.2337 118.7350   122.7495   \
> > > 255.062    100 factorial_tr_automatic_1(1000) 179.897 183.437   212.8879 \
> > > 187.8250   195.7670   979.352    100 factorial_tr_automatic_2(1000) 508.353 \
> > > 534.328   601.9643 560.7830   587.8350 1424.260    100 
> > > Cheers
> > > 
> > > On 26 Feb 2018, 21.12 +0100, Thomas Mailund <thomas.mailund@gmail.com>, wrote:
> > > > Following up on this attempt of implementing the tail-recursion optimisation \
> > > > — now that I've finally had the chance to look at it again — I find that \
> > > > non-local return implemented with callCC doesn't actually incur much overhead \
> > > > once I do it more sensibly. I haven't found a good way to handle parallel \
> > > > assignments that isn't vastly slower than simply introducing extra variables, \
> > > > so I am going with that solution. However, I have now run into another \
> > > > problem involving those local variables — and assigning to local variables \
> > > > in general. 
> > > > Consider again the factorial function and three different ways of \
> > > > implementing it using the tail recursion optimisation: 
> > > > factorial <- function(n, acc = 1) {
> > > > if (n == 1) acc
> > > > else factorial(n - 1, n * acc)
> > > > }
> > > > 
> > > > factorial_tr_manual <- function (n, acc = 1)
> > > > {
> > > > repeat {
> > > > if (n <= 1)
> > > > return(acc)
> > > > else {
> > > > .tailr_n <- n - 1
> > > > .tailr_acc <- acc * n
> > > > n <- .tailr_n
> > > > acc <- .tailr_acc
> > > > next
> > > > }
> > > > }
> > > > }
> > > > 
> > > > factorial_tr_automatic_1 <- function(n, acc = 1) {
> > > > callCC(function(escape) {
> > > > repeat {
> > > > if (n <= 1) {
> > > > escape(acc)
> > > > } else {
> > > > .tailr_n <- n - 1
> > > > .tailr_acc <- n * acc
> > > > n <- .tailr_n
> > > > acc <- .tailr_acc
> > > > }
> > > > }
> > > > })
> > > > }
> > > > 
> > > > factorial_tr_automatic_2 <- function(n, acc = 1) {
> > > > .tailr_env <- rlang::get_env()
> > > > callCC(function(escape) {
> > > > repeat {
> > > > if (n <= 1) {
> > > > escape(acc)
> > > > } else {
> > > > .tailr_env$.tailr_n <- n - 1
> > > > .tailr_env$.tailr_acc <- n * acc
> > > > .tailr_env$n <- .tailr_env$.tailr_n
> > > > .tailr_env$acc <- .tailr_env$.tailr_acc
> > > > }
> > > > }
> > > > })
> > > > }
> > > > 
> > > > The  factorial_tr_manual function is how I would implement the function \
> > > > manually while  factorial_tr_automatic_1 is what my package used to come up \
> > > > with. It handles non-local returns, because this is something I need in \
> > > > general. Finally,  factorial_tr_automatic_2 accesses the local variables \
> > > > explicitly through the environment, which is what my package currently \
> > > > produces. 
> > > > The difference between supporting non-local returns and not is tiny, but \
> > > > explicitly accessing variables through their environment costs me about a \
> > > > factor of five — something that surprised me. 
> > > > > microbenchmark::microbenchmark(factorial(1000),
> > > > +                                                factorial_tr_manual(1000),
> > > > +                                                \
> > > > factorial_tr_automatic_1(1000), +                                             \
> > > >                 factorial_tr_automatic_2(1000))
> > > > Unit: microseconds
> > > > expr       min          lq       mean    median
> > > > factorial(1000) 756.357 810.4135 963.1040 856.3315
> > > > factorial_tr_manual(1000) 104.838 119.7595 198.7347 129.0870
> > > > factorial_tr_automatic_1(1000) 112.354 125.5145 211.6148 135.5255
> > > > factorial_tr_automatic_2(1000) 461.015 544.7035 688.5988 565.3240
> > > > uq         max neval
> > > > 945.3110 4149.099    100
> > > > 136.8200 4190.331    100
> > > > 152.9625 5944.312    100
> > > > 600.5235 7798.622    100
> > > > 
> > > > The simple solution, of course, is to not do that, but then I can't handle \
> > > > expressions inside calls to "with". And I would really like to, because then \
> > > > I can combine tail recursion with pattern matching. 
> > > > I can define linked lists and a length function on them like this:
> > > > 
> > > > library(pmatch)
> > > > llist := NIL | CONS(car, cdr : llist)
> > > > 
> > > > llength <- function(llist, acc = 0) {
> > > > cases(llist,
> > > > NIL -> acc,
> > > > CONS(car, cdr) -> llength(cdr, acc + 1))
> > > > }
> > > > 
> > > > The tail-recursion I get out of transforming this function looks like this:
> > > > 
> > > > llength_tr <- function (llist, acc = 0) {
> > > > .tailr_env <- rlang::get_env()
> > > > callCC(function(escape) {
> > > > repeat {
> > > > if (!rlang::is_null(..match_env <- test_pattern(llist,
> > > > NIL)))
> > > > with(..match_env, escape(acc))
> > > > 
> > > > else if (!rlang::is_null(..match_env <-
> > > > test_pattern(llist, CONS(car, cdr))))
> > > > with(..match_env, {
> > > > .tailr_env$.tailr_llist <- cdr
> > > > .tailr_env$.tailr_acc <- acc + 1
> > > > .tailr_env$llist <- .tailr_env$.tailr_llist
> > > > .tailr_env$acc <- .tailr_env$.tailr_acc
> > > > })
> > > > }
> > > > })
> > > > }
> > > > 
> > > > Maybe not the prettiest code, but you are not supposed to actually see it, of \
> > > > course. 
> > > > There is not much gain in speed
> > > > 
> > > > Unit: milliseconds
> > > > expr         min          lq       mean    median          uq
> > > > llength(test_llist) 70.74605 76.08734 87.78418 85.81193 94.66378
> > > > llength_tr(test_llist) 45.16946 51.56856 59.09306 57.00101 63.07044
> > > > max neval
> > > > 182.4894    100
> > > > 166.6990    100
> > > > 
> > > > but you don't run out of stack space
> > > > 
> > > > > llength(make_llist(1000))
> > > > Error: evaluation nested too deeply: infinite recursion / \
> > > > options(expressions=)? Error during wrapup: C stack usage   7990648 is too \
> > > > close to the limit
> > > > > llength_tr(make_llist(1000))
> > > > [1] 1000
> > > > 
> > > > I should be able to make the function go faster if I had a faster way of \
> > > > handling the variable assignments, but inside "with", I'm not sure how to do \
> > > > that… 
> > > > Any suggestions?
> > > > 
> > > > Cheers
> > > > 
> > > > On 11 Feb 2018, 16.48 +0100, Thomas Mailund <thomas.mailund@gmail.com>, \
> > > > wrote:
> > > > > Hi guys,
> > > > > 
> > > > > I am working on some code for automatically translating recursive functions \
> > > > > into looping functions to implemented tail-recursion optimisations. See \
> > > > > https://github.com/mailund/tailr 
> > > > > As a toy-example, consider the factorial function
> > > > > 
> > > > > factorial <- function(n, acc = 1) {
> > > > > if (n <= 1) acc
> > > > > else factorial(n - 1, acc * n)
> > > > > }
> > > > > 
> > > > > I can automatically translate this into the loop-version
> > > > > 
> > > > > factorial_tr_1 <- function (n, acc = 1)
> > > > > {
> > > > > repeat {
> > > > > if (n <= 1)
> > > > > return(acc)
> > > > > else {
> > > > > .tailr_n <- n - 1
> > > > > .tailr_acc <- acc * acc
> > > > > n <- .tailr_n
> > > > > acc <- .tailr_acc
> > > > > next
> > > > > }
> > > > > }
> > > > > }
> > > > > 
> > > > > which will run faster and not have problems with recursion depths. However, \
> > > > > I'm not entirely happy with this version for two reasons: I am not happy \
> > > > > with introducing the temporary variables and this rewrite will not work if \
> > > > > I try to over-scope an evaluation context. 
> > > > > I have two related questions, one related to parallel assignments — i.e. \
> > > > > expressions to variables so the expression uses the old variable values and \
> > > > > not the new values until the assignments are all done — and one related \
> > > > > to restarting a loop from nested loops or from nested expressions in `with` \
> > > > > expressions or similar. 
> > > > > I can implement parallel assignment using something like rlang::env_bind:
> > > > > 
> > > > > factorial_tr_2 <- function (n, acc = 1)
> > > > > {
> > > > > .tailr_env <- rlang::get_env()
> > > > > repeat {
> > > > > if (n <= 1)
> > > > > return(acc)
> > > > > else {
> > > > > rlang::env_bind(.tailr_env, n = n - 1, acc = acc * n)
> > > > > next
> > > > > }
> > > > > }
> > > > > }
> > > > > 
> > > > > This reduces the number of additional variables I need to one, but is a \
> > > > > couple of orders of magnitude slower than the first version. 
> > > > > > microbenchmark::microbenchmark(factorial(100),
> > > > > + factorial_tr_1(100),
> > > > > + factorial_tr_2(100))
> > > > > Unit: microseconds
> > > > > expr min lq mean median uq max neval
> > > > > factorial(100) 53.978 60.543 77.76203 71.0635 85.947 180.251 100
> > > > > factorial_tr_1(100) 9.022 9.903 11.52563 11.0430 11.984 28.464 100
> > > > > factorial_tr_2(100) 5870.565 6109.905 6534.13607 6320.4830 6756.463 \
> > > > > 8177.635 100 
> > > > > 
> > > > > Is there another way to do parallel assignments that doesn't cost this much \
> > > > > in running time? 
> > > > > My other problem is the use of `next`. I would like to combine \
> > > > > tail-recursion optimisation with pattern matching as in \
> > > > > https://github.com/mailund/pmatch where I can, for example, define a linked \
> > > > > list like this: 
> > > > > devtools::install_github("mailund/pmatch")
> > > > > library(pmatch)
> > > > > llist := NIL | CONS(car, cdr : llist)
> > > > > 
> > > > > and define a function for computing the length of a list like this:
> > > > > 
> > > > > list_length <- function(lst, acc = 0) {
> > > > > force(acc)
> > > > > cases(lst,
> > > > > NIL -> acc,
> > > > > CONS(car, cdr) -> list_length(cdr, acc + 1))
> > > > > }
> > > > > 
> > > > > The `cases` function creates an environment that binds variables in a \
> > > > > pattern-description that over-scopes the expression to the right of `->`, \
> > > > > so the recursive call in this example have access to the variables `cdr` \
> > > > > and `car`. 
> > > > > I can transform a `cases` call to one that creates the environment \
> > > > > containing the bound variables and then evaluate this using `eval` or \
> > > > > `with`, but in either case, a call to `next` will not work in such a \
> > > > > context. The expression will be evaluated inside `bind` or `with`, and not \
> > > > > in the `list_lenght` function. 
> > > > > A version that *will* work, is something like this
> > > > > 
> > > > > factorial_tr_3 <- function (n, acc = 1)
> > > > > {
> > > > > .tailr_env <- rlang::get_env()
> > > > > .tailr_frame <- rlang::current_frame()
> > > > > repeat {
> > > > > if (n <= 1)
> > > > > rlang::return_from(.tailr_frame, acc)
> > > > > else {
> > > > > rlang::env_bind(.tailr_env, n = n - 1, acc = acc * n)
> > > > > rlang::return_to(.tailr_frame)
> > > > > }
> > > > > }
> > > > > }
> > > > > 
> > > > > Here, again, for the factorial function since this is easier to follow than \
> > > > > the list-length function. 
> > > > > This solution will also work if you return values from inside loops, where \
> > > > > `next` wouldn't work either. 
> > > > > Using `rlang::return_from` and `rlang::return_to` implements the right \
> > > > > semantics, but costs me another order of magnitude in running time. 
> > > > > microbenchmark::microbenchmark(factorial(100),
> > > > > factorial_tr_1(100),
> > > > > factorial_tr_2(100),
> > > > > factorial_tr_3(100))
> > > > > Unit: microseconds
> > > > > expr min lq mean median uq max neval
> > > > > factorial(100) 52.479 60.2640 93.43069 67.5130 83.925 2062.481 100
> > > > > factorial_tr_1(100) 8.875 9.6525 49.19595 10.6945 11.217 3818.823 100
> > > > > factorial_tr_2(100) 5296.350 5525.0745 5973.77664 5737.8730 6260.128 \
> > > > > 8471.301 100 factorial_tr_3(100) 77554.457 80757.0905 87307.28737 \
> > > > > 84004.0725 89859.169 171039.228 100 
> > > > > I can live with the "introducing extra variables" solution to parallel \
> > > > > assignment, and I could hack my way out of using `with` or `bind` in \
> > > > > rewriting `cases`, but restarting a `repeat` loop would really make for a \
> > > > > nicer solution. I know that `goto` is considered harmful, but really, in \
> > > > > this case, it is what I want. 
> > > > > A `callCC` version also solves the problem
> > > > > 
> > > > > factorial_tr_4 <- function(n, acc = 1) {
> > > > > function_body <- function(continuation) {
> > > > > if (n <= 1) {
> > > > > continuation(acc)
> > > > > } else {
> > > > > continuation(list("continue", n = n - 1, acc = acc * n))
> > > > > }
> > > > > }
> > > > > repeat {
> > > > > result <- callCC(function_body)
> > > > > if (is.list(result) && result[[1]] == "continue") {
> > > > > n <- result$n
> > > > > acc <- result$acc
> > > > > next
> > > > > } else {
> > > > > return(result)
> > > > > }
> > > > > }
> > > > > }
> > > > > 
> > > > > But this requires that I know how to distinguish between a valid return \
> > > > > value and a tag for "next" and is still a lot slower than the `next` \
> > > > > solution 
> > > > > microbenchmark::microbenchmark(factorial(100),
> > > > > factorial_tr_1(100),
> > > > > factorial_tr_2(100),
> > > > > factorial_tr_3(100),
> > > > > factorial_tr_4(100))
> > > > > Unit: microseconds
> > > > > expr min lq mean median uq max neval
> > > > > factorial(100) 54.109 61.8095 81.33167 81.8785 89.748 243.554 100
> > > > > factorial_tr_1(100) 9.025 9.9035 11.38607 11.1990 12.008 22.375 100
> > > > > factorial_tr_2(100) 5272.524 5798.3965 6302.40467 6077.7180 6492.959 \
> > > > > 9967.237 100 factorial_tr_3(100) 66186.080 72336.2810 76480.75172 \
> > > > > 73632.9665 75405.054 203785.673 100 factorial_tr_4(100) 270.978 302.7890 \
> > > > > 337.48763 313.9930 334.096 1425.702 100 
> > > > > I don't necessarily need the tail-recursion optimisation to be faster than \
> > > > > the recursive version; just getting out of the problem of too deep \
> > > > > recursions is a benefit, but I would rather not pay with an order of \
> > > > > magnitude for it. I could, of course, try to handle cases that works with \
> > > > > `next` in one way, and other cases using `callCC`, but I feel it should be \
> > > > > possible with a version that handles all cases the same way. 
> > > > > Is there any way to achieve this?
> > > > > 
> > > > > Cheers
> > > > > Thomas
> > > > > 
> > > > > 
> > > > > 
> > > > > 
> > > > > 
> > > > > 
> > > > > 
> > > > > 
> > > 
> > > [[alternative HTML version deleted]]
> > > 
> > > ______________________________________________
> > > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > > https://stat.ethz.ch/mailman/listinfo/r-help
> > > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> > > and provide commented, minimal, self-contained, reproducible code.
> 

	[[alternative HTML version deleted]]

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