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List:       php-windows
Subject:    Re: [PHP-WIN] Date Increment Problem
From:       "Stephen Edmonds" <stephen.edmonds5 () btinternet ! com>
Date:       2002-10-31 13:59:29
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60 seconds in an minute
60 minutes in an hour
24 hours in a day
3 days needed
therefor: 60 * 60 * 24 * 3

Its worth noting there are 3600 seconds in 1 hour... so you could use 3600 *
24 * 3

----- Original Message -----
From: "Constantin Baciu" <johndoe110479@mymail.ro>
To: "Stephen Edmonds" <stephen.edmonds5@btinternet.com>
Sent: Thursday, October 31, 2002 8:07 AM
Subject: Re: [PHP-WIN] Date Increment Problem


> Correct me if I am wrong, but I think that the seconds in 3 days are
60*24*3
> (as opposed to 60*60*24*3)
>
> ----- Original Message -----
> From: "Stephen Edmonds" <stephen.edmonds5@btinternet.com>
> Newsgroups: php.windows
> To: "PHP Helplist Windows" <php-windows@lists.php.net>; "Raheel Hussain"
> <raheelphp@yahoo.com>
> Sent: Wednesday, October 30, 2002 7:36 PM
> Subject: Re: [PHP-WIN] Date Increment Problem
>
>
> > Firstly, you need to understand time.
> >
> > Time in computers is stored as the number of seconds since January 1st,
> > 1970. The time now is 1035999078 (Or to humans, 17:31:30 on the 30th
Oct).
> > When you call the current time with time() it returns that long number
> > above. You can then add on 1 days worth of seconds to figure out when
> > tommorow is
> >
> > $CurrentTime = time();
> > $TommorowTime = $CurrentTime + ( 60 * 60 * 24 * 3 );
> >
> > You can then use date() to transform that number in to human form
> >
> > $HumanDate = date( d/n/y H:i, $TommorowTime );
> > print $HumanDate;
> >
> > Hope this helps
> >
> > Stephen
> >
> > ----- Original Message -----
> > From: "Raheel Hussain" <raheelphp@yahoo.com>
> > To: <php-windows@lists.php.net>
> > Sent: Wednesday, October 30, 2002 11:04 AM
> > Subject: [PHP-WIN] Date Increment Problem
> >
> >
> > >
> > > hi, I m a newbie programmer, may b solve to this prob. is a cheap
thing,
> > but i cant get solution of it.
> > >
> > > i have two variables
> > > $RegisterDate, and $ExpireDate
> > >
> > > what I want to do is the the $RegisterDate will be taken from the
> system.
> > > but the $ExpireDate will be three days after the $RegisterDate,
> > >
> > > i m doing this in the following way, but having problems, i cant find
> the
> > way to increment the data for after three days
> > >
> > > $RegisterDate=date("m/d/y");
> > > $ExpireDate=$RegisterDate + 3 //creating problem,
> > >
> > > if the register date is 10/29/01 then the expire date should be
11/2/02.
> > >
> > > plz help
> > >
> > >
> > >
> > > ---------------------------------
> > > Do you Yahoo!?
> > > HotJobs - Search new jobs daily now
> >
> >
>
>
> ------------------------------------------------------------------------
> P.S. Stiai ca s-a lansat www.FreeSMS.ro ?
>



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