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List:       php-internals
Subject:    Re: [PHP-DEV] Variable Scope
From:       LingWitt () insightbb ! com
Date:       2003-08-31 13:23:20
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On Sunday, Aug 31, 2003, at 07:36 America/New_York, Jeremy Johnstone 
wrote:

> It ain't gonna happen, so why continue to make an ass of yourself?
>
> When you get three of the top people in PHP's development telling you 
> it
> will NEVER happen, then you should really pay attention! No amount of
> explaining, complaining, bitching, or whining will change that fact, so
> why waste everyones type with your posts?

I never bitched, wined, or truly complained. The first gerund is indeed 
correct.

>
> I am not trying to be rude in the least bit, but you obviously aren't

Now whose being an ass! hypocrite!

> taking the hint from them to drop it. People like yourself make it hard

I ENDED THE THREAD LONG AGO, ONLY TO BE PULLED BACK IN BY COMMENTS LIKE 
THIS.

> to ever get responses from the top people, because they get burned out
> by people like you.

Then give them something provocative to discuss, as I did.

>
>
> Jeremy
>
>
> On Sat, 2003-08-30 at 21:33, LingWitt@insightbb.com wrote:
>> I am saying that perhaps the for loop should treat that part as a
>> declaratory statement and mask outer variables.
>>
>> On Saturday, Aug 30, 2003, at 15:28 America/New_York, Rasmus Lerdorf
>> wrote:
>>
>>> Yes, but you are adding a declaration separate from the for loop 
>>> there.
>>> So not the same at all given there is no declaration in PHP.
>>>
>>> On Sat, 30 Aug 2003 LingWitt@insightbb.com wrote:
>>>
>>>> Not so. I supplied this version earlier:
>>>>
>>>> int array[] = {1, 2, 3, 4, 5};
>>>>
>>>> for (int i = 0; i < 5; i++)
>>>> {
>>>>          int num = array[i];
>>>>          printf("%d", num);
>>>>          for (int i = 0; i < 5; i++)
>>>>                  printf("%d", i * num);
>>>> }
>>>>
>>>> On Saturday, Aug 30, 2003, at 15:19 America/New_York, Rasmus Lerdorf
>>>> wrote:
>>>>
>>>>> It was based on the for construct from C and works exactly the same
>>>>> way.
>>>>
>>>
>

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