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List:       php-general
Subject:    Re: [PHP] for loop inside a switch
From:       129.219.114.119
Date:       2007-08-31 22:56:52
Message-ID: 39.37.39364.3DC98D64 () pb1 ! pair ! com
[Download RAW message or body]

Sanjeev is right.  You're thinking about the problem backwards.  You're 
trying to build a Switch inside a loop.  Remember, if you ever have to do 
some operating multiple times you're using a forloop, then the thing that 
you want to repeat(switch case) is INSIDE the for loop.

- Dan

""Sanjeev N"" <snsanju@gmail.com> wrote in message 
news:46c5cacf.11bd720a.213d.3518@mx.google.com...
> This will not work at all..
> Instead of switch try with if condition as follows
>
> for ($i=0; $i <21; $i++) {
> if(faq$i == $q){
>     echo $faq1;
>     break;
> }
> }
> Now it works..
>
> You can write the code to display the result how you want.. but you cant
> write the code to write a code :)
>
> Cheers
>
> Warm Regards,
> Sanjeev
> http://www.sanchanworld.com
> http://webdirectory.sanchanworld.com - Submit your website URL
> http://webhosting.sanchanworld.com - Choose your best web hosting plan
> -----Original Message-----
> From: Hulf [mailto:ross@blue-fly.co.uk]
> Sent: Thursday, August 16, 2007 3:11 PM
> To: php-general@lists.php.net
> Subject: [PHP] for loop inside a switch
>
> Hi,
>
> switch ($q) {
>
> for ($i=0; $i <21; $i++) {
> case 'faq$i':
>    echo $faq1;
>    break;
> }
> }
>
>
> I just want to loop out a big long list of cases.
>
> -- 
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