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List: pcc-list
Subject: long long shift?
From: Iain Hibbert <plunky () rya-online ! net>
Date: 2011-07-03 20:40:15
Message-ID: alpine.NEB.2.00.1107032127250.5896 () galant ! ukfsn ! org
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Hi
while looking at that problem from Szabolcs Nagy, I noticed that the code
for some previous lines, such as
*(md++) = (unsigned char)(t>>40);
was emitted as
movb $40,%cl
movl %esi,%eax
movl %edi,%edx
shrdl %edx,%eax
shrl %cl,%edx
testb $32,%cl
je 1f
movl %edx,%eax
xorl %edx,%edx
1:
movl 8(%ebp),%edx
incl %edx
movl %edx,8(%ebp)
movb %al,-1(%edx)
but I'm wondering about the testb halfway down (ignoring the fact that we
are dealing with a const today), does it mean to sidestep the shifting
when cl == sizeof long? it seems to me that the shift is already done..
should the test not be done before the shrdl stuff?
regards,
iain
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