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List:       openembedded-core
Subject:    [OE-core] [PATCH 7/8] oeqa.utils.metadata: have layer name as an attribute in xml
From:       Markus Lehtonen <markus.lehtonen () linux ! intel ! com>
Date:       2016-12-28 13:02:43
Message-ID: 1482930164-15721-8-git-send-email-markus.lehtonen () linux ! intel ! com
[Download RAW message or body]

Have the layer name as an attribute instead of of the name of the
element itself. That is, have <layer name="layer_name"/> instead of
<layer_name/>. A bit better XML design.

[YOCTO #10590]

Signed-off-by: Markus Lehtonen <markus.lehtonen@linux.intel.com>
---
 meta/lib/oeqa/utils/metadata.py | 8 +++++---
 1 file changed, 5 insertions(+), 3 deletions(-)

diff --git a/meta/lib/oeqa/utils/metadata.py b/meta/lib/oeqa/utils/metadata.py
index d5cc290..6331c21 100644
--- a/meta/lib/oeqa/utils/metadata.py
+++ b/meta/lib/oeqa/utils/metadata.py
@@ -90,12 +90,14 @@ def write_metadata_file(file_path, metadata):
     with open(file_path, 'w') as f:
         f.write(xml_doc.toprettyxml())
 
-def dict_to_XML(tag, dictionary):
+def dict_to_XML(tag, dictionary, **kwargs):
     """ Return XML element converting dicts recursively. """
 
-    elem = Element(tag)
+    elem = Element(tag, **kwargs)
     for key, val in dictionary.items():
-        if isinstance(val, MutableMapping):
+        if tag == 'layers':
+            child = (dict_to_XML('layer', val, name=key))
+        elif isinstance(val, MutableMapping):
             child = (dict_to_XML(key, val))
         else:
             child = Element(key)
-- 
2.6.6

-- 
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