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List:       log4j-dev
Subject:    Hot log only message without class name.
From:       "sudhakar tadepalli" <sudhakartv () hotmail ! com>
Date:       2002-08-27 21:37:04
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Hi ,
I have configured log4j for my project and developed a wraper class as 
log.java by using Logger.java
ex.
public static void debug(Class source, String msg) {
		init();

		Logger log = Logger.getLogger(source.getName());
		log.debug(msg);

	}
public static void debug(Object source, String msg) {
		Log.debug(source.getClass(), msg);
	}

If use these methods I need to pass class and message as parameters.If i 
just want to pass only message how to overload debug method.?
I tried like this.

public static void debug(String msg) {
		Log.debug(msg);
	}

I have used like this in my test class.

Log.debug("Test message");

But result is: "Test Message.Test Message"

Why it is doing like that.Have any idea?

Thanks.
Sudhakar




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