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List:       kde-i18n-doc
Subject:    koffice/kspread/functions
From:       Luciano Montanaro <mikelima () cirulla ! net>
Date:       2007-11-18 9:50:50
Message-ID: 1195379450.219013.25733.nullmailer () svn ! kde ! org
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SVN commit 738205 by montanaro:

Fixed error found by Yukiko Bando (and a similar one, a few messages below)
CCMAIL: Yukiko Bando <ybando@k6.dion.ne.jp>
CCMAIL: kde-i18n-doc@kde.org


 M  +2 -2      bitops.xml  


--- trunk/koffice/kspread/functions/bitops.xml #738204:738205
@@ -18,7 +18,7 @@
       <Help>
 	<Text>The BITAND() function performs a bit-wise AND operation for the two integer \
parameters.</Text>  <Syntax>BITAND(value; value)</Syntax>
-	<Example>BITAND(12;10) returns 8 (because decimal 12 is binary 1100, and decimal 10 \
is binary 0100; and 1100 "anded" with 0110 is 0100, which is integer 8).</Example> \
+	<Example>BITAND(12;10) returns 8 (because decimal 12 is binary 1100, and decimal 10 \
is binary 1010; and 1100 "anded" with 1010 is 1000, which is integer 8).</Example>  \
<Related>BITOR</Related><Related>BITXOR</Related>  </Help>
     </Function>
@@ -92,7 +92,7 @@
       <Help>
 	<Text>The BITXOR() function performs a bit-wise exclusive-OR operation for the two \
integer parameters. </Text>  <Syntax>BITXOR(value; value)</Syntax>
-	<Example>BITXOR(12;10) returns 6 (because decimal 12 is binary 1100, and decimal 10 \
is binary 1100; and 1100 "xored" with 1010 is 0110, which is integer 6).</Example> \
+	<Example>BITXOR(12;10) returns 6 (because decimal 12 is binary 1100, and decimal 10 \
is binary 1010; and 1100 "xored" with 1010 is 0110, which is integer 6).</Example>  \
<Related>BITAND</Related><Related>BITOR</Related>  </Help>
     </Function>


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