Am Mittwoch, 26. April 2006 22:27 schrieb Dmitry Suzdalev:
> On Thursday 27 April 2006 00:12, Will Entriken wrote:
> > std::numeric_limits<double>::min() return the minimum positive value.
>
> Hmm... yes? :)
> Bahhh, I should read docs more carefully, thanks! :)
>
> > you could try maxd = -1 if d will be non-negative. that will be pretty
> > obvious what is going on.
>
> Nope, d might be negative - that's why I didn't use -1 for maxd.
> So, then another question:
> Maybe I'm wrong when I say that
> "-std::numeric_limits<double>::max()" is messy-looking?

If you need a value that is smaller than all numbers, you could use:

maxd = - std::numeric_limits<double>::infinity();

Christoph
 
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