i think that looks find, unless you know the first value of d, before
you enter the loop, just make it that.

good luck
-WE

On 4/26/06, Dmitry Suzdalev <dimsuz@gmail.com> wrote:
> On Thursday 27 April 2006 00:12, Will Entriken wrote:
> > std::numeric_limits<double>::min() return the minimum positive value.
> Hmm... yes? :)
> Bahhh, I should read docs more carefully, thanks! :)
>
> > you could try maxd = -1 if d will be non-negative. that will be pretty
> > obvious what is going on.
> Nope, d might be negative - that's why I didn't use -1 for maxd.
> So, then another question:
> Maybe I'm wrong when I say that
> "-std::numeric_limits<double>::max()" is messy-looking?
>
> Now that I know (thanks, Will), that min() return minimum _positive_ value, I
> think that using -max() is all right. Is this so?
>
> Thanks!
> Dmitry.
>
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