From kde-devel  Tue Mar 29 07:55:13 2005
From: Frans Englich <frans.englich () telia ! com>
Date: Tue, 29 Mar 2005 07:55:13 +0000
To: kde-devel
Subject: KURL, encode/decode
Message-Id: <200503290803.10920.frans.englich () telia ! com>
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Hello,

In a scenario, I need to, when given a string which either is an properly 
encoded URI or an un-encoded(invalid) URI, transform it to a valid URI.

For example, no matter if the input is "test with spaces" or 
"test%20with%20spaces", the output should be "test%20with%20spaces". The 
algorithm should be idempotent, in other words.

The following algorithm /appears/ to achieve what I want, but I find it 
costly(python example):

def absolutizeURI(string):

        u = KURL(string)

        if u.isValid():
                return u.url()
        else:
                return KURL.encode_string(KURL.decode_string(string))


E.g, a handful of encode/decode loops have parsed the string.

I wonder, what is the proper way of achieving what I want?

BTW, I've attached a small Python test case to play with.


Cheers,

		Frans

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import libxml2
import libxslt
import sys

def openXmlFile( uri, schemaURL ):

    return libxml2.parseFile( uri )

    #return openXmlDocument( document, schemaURL )


file = "t.xsl"
xsltDoc = openXmlFile( file, None )     
xslt = libxslt.parseStylesheetDoc( xsltDoc )     
self.sheets[key][0] = xsltDoc     
self.sheets[key][1] = xslt     

for xslt in self.sheets.values():    
    if xslt[0]:    
        xslt[0].freeDoc()    

# vim: set et tw=80 ts=4 sw=4 sts=4:

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