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List:       cifs-protocol
Subject:    [cifs-protocol] 2106010040000444 [MS-DNSP] StartScavenging RPC call
From:       Sreekanth Nadendla via cifs-protocol <cifs-protocol () lists ! samba ! org>
Date:       2021-06-01 3:52:33
Message-ID: BN8PR21MB1252F930EBCF409C40A39476C53E9 () BN8PR21MB1252 ! namprd21 ! prod ! outlook ! com
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Dochelp in Bcc

Hello Douglas, thank you for your question regarding the MS-DNSP specification. We \
have created incident 2106010040000444  to track the investigation. One of the open \
specifications team member will contact you shortly.

Regards,
Sreekanth Nadendla
Microsoft Windows Open Specifications

-----Original Message-----
From: Douglas Bagnall <douglas.bagnall@catalyst.net.nz> 
Sent: Monday, May 31, 2021 10:45 PM
To: Interoperability Documentation Help <dochelp@microsoft.com>; \
                cifs-protocol@lists.samba.org
Subject: [EXTERNAL] [MS-DNSP] StartScavenging RPC call

hi Dochelp,

I would like some clarification of the StartScavenging Operation as mentioned in \
3.1.4.1 R_DnssrvOperation (and implied in R_DnssrvOperation2, etc).

The fullest description of the call is:

> If pszOperation is StartScavenging, the server MUST initiate a resource record \
> scavenging cycle on the DNS server, and return success.

While in another place (3.1.1.1.1, discussing ScavengingInterval), it says

> If the value is non-zero and a StartScavenging operation is initiated, the value is \
> ignored and scavenging begins immediately.

The terms I would like clarification on are "resource record scavenging"
and "begins immediately".

Does "resource record scavenging" refer to:

a) turning stale dynamic records into DNS tombstones when aging is enabled for the \
zone and server.

b) removing tombstoned nodes and records after the appropriate time.

c) both a) and b).

d) something else?


Does "begins immediately" imply a scavengable DNS resource should disappear within a \
few seconds on an unloaded server with a very small zone? Or does the "resource \
record scavenging cycle" have aspects that mean this is not expected?

cheers,
Douglas
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