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List:       bitcoin-dev
Subject:    [Bitcoin-development] BIP39 word list
From:       slush () centrum ! cz (slush)
Date:       2013-10-24 13:26:32
Message-ID: CAJna-Hjap-GPc-rTQsYxVqjvigZ3y8YDQmL++b2Gw0SAC7QLQA () mail ! gmail ! com
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I've just pushed updated wordlist which is filtered to similar characters
taken from this matrix.

BIP39 now consider following character pairs as similar:

        similar = (
            ('a', 'c'), ('a', 'e'), ('a', 'o'),
            ('b', 'd'), ('b', 'h'), ('b', 'p'), ('b', 'q'), ('b', 'r'),
            ('c', 'e'), ('c', 'g'), ('c', 'n'), ('c', 'o'), ('c', 'q'),
('c', 'u'),
            ('d', 'g'), ('d', 'h'), ('d', 'o'), ('d', 'p'), ('d', 'q'),
            ('e', 'f'), ('e', 'o'),
            ('f', 'i'), ('f', 'j'), ('f', 'l'), ('f', 'p'), ('f', 't'),
            ('g', 'j'), ('g', 'o'), ('g', 'p'), ('g', 'q'), ('g', 'y'),
            ('h', 'k'), ('h', 'l'), ('h', 'm'), ('h', 'n'), ('h', 'r'),
            ('i', 'j'), ('i', 'l'), ('i', 't'), ('i', 'y'),
            ('j', 'l'), ('j', 'p'), ('j', 'q'), ('j', 'y'),
            ('k', 'x'),
            ('l', 't'),
            ('m', 'n'), ('m', 'w'),
            ('n', 'u'), ('n', 'z'),
            ('o', 'p'), ('o', 'q'), ('o', 'u'), ('o', 'v'),
            ('p', 'q'), ('p', 'r'),
            ('q', 'y'),
            ('s', 'z'),
            ('u', 'v'), ('u', 'w'), ('u', 'y'),
            ('v', 'w'), ('v', 'y')
        )

Feel free to review and comment current wordlist, but I think we're slowly
moving forward final list.

slush


On Sat, Oct 19, 2013 at 1:58 AM, Gregory Maxwell <gmaxwell at gmail.com> wrote:

> some fairly old wordlist solver code of mine:
> 
> https://people.xiph.org/~greg/wordlist.visual.py
> 
> it has a 52x52 letter visual similarity matrix in it (along with a
> citation)
> 
> On Fri, Oct 18, 2013 at 4:52 PM, jan <jan.marecek at gmail.com> wrote:
> > 
> > The words 'public', 'private' and 'secret' could be confusing when
> > encoding public and private keys. eg. a private key that begins with
> > the word 'public'.
> > 
> > I think avoiding words that could look similar when written down would
> > be a good idea aswell. I searched for words that only differ by the
> > letters c & e, g & y, u & v and found the following:
> > 
> > car ear
> > cat eat
> > gear year
> > value valve
> > 
> > Other combinations could potentially be problematic depending on the
> > handwriting style: ft, ao, ij, vy, possibly even lt and il?
> > 
> > I've included the search utility I used below.
> > 
> > 
> > #include <stdbool.h>
> > #include <string.h>
> > #include <stdio.h>
> > 
> > char *similar_char_pairs[] = { "ce", "gy", "uv", NULL };
> > 
> > bool is_similar_char(char c1, char c2)
> > {
> > char **pairs = similar_char_pairs;
> > do {
> > char *p = *pairs;
> > if ((c1 == p[0] && c2 == p[1]) ||
> > (c1 == p[1] && c2 == p[0]))
> > return true;
> > } while (*++pairs);
> > 
> > return false;
> > }
> > 
> > bool print_words_if_similar(char *word1, char *word2)
> > {
> > /* reject words of different lengths */
> > if (strlen(word1) != strlen(word2))
> > return false;
> > 
> > size_t i, similarcount = 0;
> > 
> > for (i = 0; i < strlen(word1); i++) {
> > /* skip identical letters */
> > if (word1[i] == word2[i])
> > continue;
> > 
> > /* reject words that don't match */
> > if (is_similar_char(word1[i], word2[i]) == false)
> > return false;
> > 
> > similarcount++;
> > }
> > 
> > /* reject words with more than 1 different letter */
> > //if (similarcount > 1)
> > //  return false;
> > 
> > printf("%s %s\n", word1, word2);
> > 
> > return true;
> > }
> > 
> > int main(void)
> > {
> > /* english.txt is assumed to exist in the working directory
> > download from:
> > 
> https://github.com/trezor/python-mnemonic/blob/master/mnemonic/wordlist/english.txt*/
> 
> > FILE* f = fopen("english.txt", "r");
> > if (!f) {
> > fprintf(stderr, "failed to open english.txt\n");
> > return 1;
> > }
> > 
> > /* read in word list, assumes one word per line */
> > #define MAXWORD 16
> > char wordlist[2048][MAXWORD];
> > int word = 0;
> > while (fgets(wordlist[word], MAXWORD, f)) {
> > /* strip trailing whitespace, assumes no leading whitespace */
> > char *ch = strpbrk(wordlist[word], " \n\t");
> > if (ch)
> > *ch = '\0';
> > word++;
> > }
> > 
> > if (word != 2048) {
> > fprintf(stderr, "word list incorrect length\n");
> > return 1;
> > }
> > 
> > /* check each word for similarity against every other word */
> > int i, j, count = 0;
> > for (i = 0; i < 2048; i++) {
> > for (j = i+1; j < 2048; j++) {
> > if (print_words_if_similar(wordlist[i], wordlist[j]))
> > count++;
> > }
> > }
> > 
> > printf("%d matches\n", count);
> > 
> > return 0;
> > }
> > 
> > 
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> 
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> from
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