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List:       apache-modperl
Subject:    RE: any way to get the uri path part that matches $r->location?
From:       Mark Hedges <Mark.Hedges () Ticketmaster ! com>
Date:       2014-06-23 22:38:28
Message-ID: 55EEF0B3C5BF2744B2248754D717EE4C4B342F () USASHEXMB02 ! LYV ! LiveNation ! com
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I was thinking about this, I think I can do something like:

my $loc = $r->location;
$loc =~ s{/$}{};
my ($loc_match, $rest_of_path) = $r->uri =~ m{^(\Q$loc\E.*?/)(.*?)$}mxs;

I will try it out when I get a chance.

Mark

-----Original Message-----
From: Mark Hedges 
Sent: Monday, June 23, 2014 12:42 AM
To: mod_perl list
Cc: Mark Hedges
Subject: any way to get the uri path part that matches $r->location?

In Apache2::Controller the dispatch mechanism gets the URI into a variable, then \
removes $r->location from the start of it to get the remaining parts of the path, to \
determine which controller method to invoke.

This works for <Location> conf but not <LocationMatch>, because $r->location reports \
the string from the config block instead of the part of the path that matched it.  If \
that is a weird pattern, then it is not found in the literal URI.

Is there a way to get at what part of the URI matched the <Location> or \
<LocationMatch> directive?

Thanks.

Mark


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